Correct!!!

With sodium ethoxide, virtually only (about 100 %) E2 elimination occurs. By the abstraction of the β proton through the strong base ethoxide early in of reaction, the formation of the carbenium ion is prevented, although this tertiary carbenium ion could otherwise be formed easily. As a result, the treatment of tertiary alkyl halides with strong bases primarily leads to E2 elimination and not to E1 elimination or an ${\text{S}}_{\text{N}}1$ reaction. Due to very strong steric interactions in the trigonal bipyramidal transition state, ${\text{S}}_{\text{N}}2$ reactions with tertiary alkyl halides are almost impossible.