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Subject - Organic Chemistry
E1 eliminations are two-step processes. In the first, rate-determining step the molecule loses the leaving group, thereby forming a carbenium ion (carbocation) which, in the second step, rapidly loses a proton to Lewis bases to generate a double bond. If the base contains several protons available for , the reaction gives a product mixture of several isomers.
E1 eliminations compete with. The result of the reactions is determined by the reaction conditions, such as solvent, and the base itself.